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How to return $http.post() object with factory function

save: function(url, obj, errors, not_show_error_toast) {            
    var defer = $.Deferred();

    not_show_error_toast = typeof not_show_error_toast !== 'undefined' ? not_show_error_toast : false;

    if (angular.isDefined(obj.id)) {
        loaderShow(); // NOTE: let create manage the loader start if it needs to
        $http.put(url + obj.id + '/', obj).
            then(function onSuccess(response) {
                loaderHide();
                // HACK: because .then is used instead of .success, you probably want the response.data, please review this
                angular.extend(obj, response.data);

                defer.resolve(obj);
            }, function onError(response) {
                loaderHide();
                handleErrors(response, status, errors, not_show_error_toast);

                defer.reject(response);
            });
    } else {
        // If create is a deferral, it should be safe to return it directly
        return this.create(url, obj, errors, not_show_error_toast);
    }

    return defer.promise();
},
 
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Tagged: #How #return #object #factory #function
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