CODE EXAMPLE FOR PYTHON

uri 1045 solution in c

#include <stdio.h>

int main(){
    double a,b,c;

    scanf("%lf %lf %lf", &a, &b, &c);

    if(a >= (b+c) || b >= (a+c) || c >= (a+b))
         printf("NAO FORMA TRIANGULO
");
    else if(a*a == (b*b + c*c) || b*b == (a*a + c*c) || c*c == (a*a + b*b))
           printf("TRIANGULO RETANGULO
");
    else if(a*a > (b*b + c*c) || b*b > (a*a + c*c) || c*c > (a*a + b*b))
           printf("TRIANGULO OBTUSANGULO
");
    else if(a*a < (b*b + c*c) || b*b < (a*a + c*c) || c*c < (a*a + b*b))
           printf("TRIANGULO ACUTANGULO
");
    if(a == b && a == c)
            printf("TRIANGULO EQUILATERO
");
    if((a == b && a != c)  || (a == c && a != b) || (b == c && b != a))
            printf("TRIANGULO ISOSCELES
");

 return 0;
    
}