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first n even numbers sum javascript

// return the sum of the first n even numbers recursively. Assume n > 0

function firstEvenNumbersSum(n) {
    if (n === 0) {
        return 0;
    }
    let num = (n * 2);
    let sum = num + firstEvenNumbersSum(n-1)
    return sum;
}
 
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Tagged: #numbers #sum #javascript
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3+2 =