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maximum subarray solution leetcode

def approach3(nums):
    ans = nums[0]
    subarr_sum = nums[0]

    for i in range(1, len(nums)):
        subarr_sum = max(nums[i], nums[i] + subarr_sum)
        ans = max(ans, subarr_sum)

    return ans
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Tagged: #maximum #subarray #solution #leetcode
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2+3 =