//[10, 20, 20, 10, 10, 30, 50, 10, 20]
//There is two pair of color 10 and one of color 20. There are three odd socks left. The number of pairs is 3.
function totalPair(n, ar) {
let duplicateArray = [...ar]
let duplicate = 0
ar.forEach(col=>{
let pairs = 0;
duplicateArray.forEach(c=>{
if(c === col){
pairs++
}
})
duplicateArray = duplicateArray.filter(a=>a!==col)
duplicate += Math.floor(pairs / 2)
})
return duplicate
}