C

size of an array c

int a[20];
int length;
length = sizeof(a) / sizeof(int);

c define array size

#define ARRAY_SIZE(x) (sizeof(x) / sizeof((x)[0]))

array length c

int prices[5] = { 1, 2, 3, 4, 5 };

int size = sizeof prices / sizeof prices[0];

printf("%u", size); /* 5 */

size of an array c

int a[]= { 1, 2, 3, 4, 5, 6, 7 };
int length = sizeof(a) / sizeof(a[0]); //return 7

c how to find size of array

int a[17];
size_t n = sizeof(a)/sizeof(a[0]);

get length of array in c

int a[17];
size_t n = sizeof(a)/sizeof(a[0]);

c array len

#define len(arr) sizeof(arr) / sizeof(arr[0])

find length of array in c

int a[17]; // initializing an array
int length = sizeof(a)/sizeof(a[0]); // divide array size(in byte)/ size of the first element of the array of the same type, here int(integer size is 4byte)

increase size of array in c

#include <stdio.h>#include <stdlib.h>int main(){//a pointer to dynamically allocated memory from the heap is returned.	int *a = (int *) malloc(20 * sizeof(int));for(int i = 0; i < 20; i++)a[i] = i + 1;printf("
The contents of the array are: 
");for(int i = 0; i < 20; i++)printf("%d	", a[i]);realloc(a, 40);for(int