CPP

nearest integer rounding in c++

 cout << "Nearest value of x :" << round(x) << "
"; 

round c++

#include<bits/stdc++.h>

int main() {
	using namespace std;
	ios_base::sync_with_stdio(false), cin.tie(nullptr);

	int T; cin >> T;
	for (int case_num = 1; case_num <= T; case_num ++) {

		int64_t L, R; cin >> L >> R; R++;
		bool parity = 0;
		int64_t coeff = 1;
		int64_t ans = 0;
		while (L < R) {
			assert(1 <= L && L < R);
			auto is_good = [&](int64_t v) {
				assert(v > 0);
				bool d = v % 2;
				while (v > 0) {
					if (v % 2 != d) return false;
					d = !d;
					v /= 10;
				}
				return d == 0;
			};
			while (L < R && L % 10 != 0) {
				if (is_good(L)) {
					ans += coeff;
				}
				L++;
			}
			while (L < R && R % 10 != 0) {
				--R;
				if (is_good(R)) {
					ans += coeff;
				}
			}

			if (L == R) break;
			assert(L % 10 == 0 && R % 10 == 0);
			assert(L >= 10);

			L /= 10;
sorry for the error 

round c++

value   round   floor   ceil    trunc
-----   -----   -----   ----    -----
2.3     2.0     2.0     3.0     2.0
3.8     4.0     3.0     4.0     3.0
5.5     6.0     5.0     6.0     5.0
-2.3    -2.0    -3.0    -2.0    -2.0
-3.8    -4.0    -4.0    -3.0    -3.0
-5.5    -6.0    -6.0    -5.0    -5.0