public int max()
{
int max = elementData[0];
for (int i = 1; i < size; i++)
{
if (elementData[i] > max)
{
max = elementData[i];
}
}
return max;
}
public static double max(double[] arr) {
double result = arr[0];
for (int i = 1; i < arr.length; ++i) {
if (result < arr[i]) result = arr[i];
}
return result;
}
public static double arrayMax(double[] arr) {
double max = Double.NEGATIVE_INFINITY;
for(double cur: arr)
max = Math.max(max, cur);
return max;
}
public static String max(String[] arr) {
String result = arr[0];
for (int i = 1; i < arr.length; ++i) {
if (result.compareTo(arr[i]) < 0) result = arr[i];
}
return result;
}
Integer[] num = { 2, 4, 7, 5, 9 };
// using Collections.min() to find minimum element
// using only 1 line.
int min1 = Collections.min(Arrays.asList(num));
// using Collections.max() to find maximum element
// using only 1 line.
int max1 = Collections.max(Arrays.asList(num));
System.out.println(min1); // 2
System.out.println(max1); // 9
public static void main(String[] args) {
int [] arr = {100,200,300,50,40,-10,-50};
int max = Integer.MIN_VALUE;
for(int each: arr)
if(each > max)
max = each;
System.out.println(max); // 300
import java.util.Random;
public class Main {
public static void main(String[] args) {
int a[] = new int [100];
Random rnd = new Random ();
for (int i = 0; i< a.length; i++) {
a[i] = rnd.nextInt(99-0)+0;
System.out.println(a[i]);
}
int max = 0;
for (int i = 0; i < a.length; i++) {
a[i] = max;
for (int j = i+1; j<a.length; j++) {
if (a[j] > max) {
max = a[j];
}
}
}
System.out.println("Max element: " + max);
}
}
int[] /*OR*/ double[] /*OR*/ float[] array_of_numbers = {/*Whatever values you want*/}
/*For this example we're just using a regular integer array*/
int max = 0; /*Important to initialise the max value as ZERO*/
for (int i = 0; i < array_of_numbers.length; i++) {
if(array_of_numbers[i] > max) { /* So now we can make the comparison*/
max = array_of_numbers[i]; /* If larger, make it the new maximum*/
}
}
System.out.println("Maximum value in array: " + max)
Max_Array_size = Integer.MAX_VALUE = 2,147,483,647;
public static double max(double[] arr) {
double result = Double.NEGATIVE_INFINITY;
for (int i = 0; i < arr.length; ++i) {
if (result < arr[i]) result = arr[i];
}
return result;
}