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javascript array includes another array

const array1= ["cheese", "dough", "sauce", "pepperoni"]
const array2= ["mozzarella", "peppers", "chicken", "cheese"]

const isIncluded =  array1.some(value => array2.includes(value))
// true

const values = array1.filter(value => array2.includes(value))
// "cheese"
Comment

JavaScript find elements in array that matches another array

let haveItList = ['apples', 'milk', 'bread', 'peanutbutter'];
let wishList = ['cookies', 'bread', 'jam', 'peanutbutter', 'bananas', 'cheese'];

let inBothLists = wishList.filter(element => haveItList.includes(element));
// inBothLists = ['apples', 'bread', 'peanutbutter'];
Comment

javascript check if elements of one array are in another

const found = arr1.some(r=> arr2.includes(r))
Comment

How to check if array includes a value from another array in JavaScript

// How to check if array includes a value from another array in JavaScript
const includesAny = (arr, values) => values.some(v => arr.includes(v));
includesAny([1, 2, 3, 4], [2, 9]); // true
includesAny([1, 2, 3, 4], [8, 9]); // false
Comment

how to check all elements in array includes in another array javascript

// how to check all elements in array includes in another array javascript
const includesAll = (arr, values) => values.every(v => arr.includes(v));
includesAll([1, 2, 3, 4], [1, 4]); // true
includesAll([1, 2, 3, 4], [1, 5]); // false
Comment

javascript check if array is subset of another

let superSet = ['B', 'C', 'A', 'D'];
let subSet = ['D', 'C'];
let mixedSet = new Set([...superSet, ...subSet]);
let isSubset = mixedSet.size == superSet.length
Comment

if array ontains any item of another array js

const found = arr1.some(r=> arr2.indexOf(r) >= 0)
Comment

find items in array not in another array javascript

var arr1 = [
    {
      "prop1": "value1",
      "prop2": "value2",
    },
    {
      "prop1": "value3",
      "prop2": "value4",
    },
    {
      "prop1": "value5",
      "prop2": "value6",
    },
  ];

var arr2 = ['value1','value3', 'newValue'];

// finds all the elements of arr2 that are not in arr1
arr2.filter( 
    val => !arr1.find( arr1Obj => arr1Obj.prop1 === val)
); // outputs "newValue"
Comment

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