const array1 = ['a','b','c'];
const array2 = ['c','c','d','e'];
const array3 = [...new Set([...array1,...array2])];
console.log(array3); // ["a", "b", "c", "d", "e"]
array1 = array1.filter(function(val) {
return array2.indexOf(val) == -1;
});
// Or, with the availability of ES6:
array1 = array1.filter(val => !array2.includes(val));
let array1 = ['a','b','c'];
let array2 = ['c','c','d','e'];
let array3 = array1.concat(array2);
array3 = [...new Set([...array1,...array2])]; // O(n)