JAVASCRIPT

max value in array javascript

// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });

// For arrays with relatively few elements you can use apply: 
const max = Math.max.apply(null, arr);

// or spread operator:
const max = Math.max(...arr);

find min and max date in array javascript

const dates = [];
dates.push(new Date('2011/06/25'));
dates.push(new Date('2011/06/26'));
dates.push(new Date('2011/06/27'));
dates.push(new Date('2011/06/28'));
const maxDate = new Date(Math.max.apply(null, dates));
const minDate = new Date(Math.min.apply(null, dates));

javascript max array

var values = [3, 5, 6, 1, 4];

var max_value = Math.max(...values); //6
var min_value = Math.min(...values); //1

max and min value in array

 public static void main(String[] args) {

        int[] xr = {2, 4, 1, 3, 7, 5, 6, 10, 8, 9};

        //find maximum value
        int max = xr[0];
        for (int i = 0; i < xr.length; i++) {
            if (xr[i] > max) {
                max = xr[i];
            }
        }

        //find minimum value
        int min=xr[0];
        for (int i = 0; i <xr.length ; i++) {
            if (xr[i]<min){
                min=xr[i];
            }
        }

        System.out.println("max: "+max);
        System.out.println("min: "+min);
    }

javascript min max array

Math.max(1, 2, 3)    // 3
Math.min(1, 2, 3)    // 1

var nums = [1, 2, 3]
Math.min(...nums)    // 1
Math.max(...nums)    // 3

max value from array in javascript

// For regular arrays:
var max = Math.max(...arrayOfNumbers);

// For arrays with tens of thousands of items: 
let max = testArray[0];  //here we have considered max to the first element because we don't know which is max yet.
for (let i = 1; i < testArrayLength; ++i) { 
  if (testArray[i] > max) {  //in each iteration it will compare if the value is greater than the current considered value (we just considered first element)
    max = testArray[i]; //in the above iteration if the testArray find value/element greater than max then this new max value will be considered as Max (this will happen until the max value found).
  }
}

find max and min value in array javascript

var numbers = [1, 2, 3, 4];
Math.max(...numbers) // 4
Math.min(...numbers) // 1

js max array

Math.min(...arr) // min
Math.max(...arr) // max

Max Number from Array in JS

function arrayMax(array) {
  return array.reduce(function(a, b) {
    return Math.max(a, b);
  });
}

function arrayMin(array) {
  return array.reduce(function(a, b) {
    return Math.min(a, b);
  });
}

how to return the max and min of an array in javascript

function minMax(arr) {
  return [Math.min(...arr), Math.max(...arr)];
}

js max array

Math.max(...array);

js max with array

var myArray = [5, 10, 50];
Math.max(myArray);    // Error: NaN
Math.max.apply(Math, myArray);    // 50

get min/max array

function arrayMin(arr) {
  return arr.reduce(function (p, v) {
    return ( p < v ? p : v );
  });
}

function arrayMax(arr) {
  return arr.reduce(function (p, v) {
    return ( p > v ? p : v );
  });
}

Math max with array js

var nums = [1, 2, 3]
Math.min.apply(Math, nums)    // 1
Math.max.apply(Math, nums)    // 3
Math.min.apply(null, nums)    // 1
Math.max.apply(null, nums)    // 3

javascript Using Math.max() on an Array

function myArrayMax(arr) {
  return Math.max.apply(null, arr);
}

array max value

const findMax = (arr)=>{
    let max = 0 ;
   for (let index = 0; index < arr.length; index++) {
        if (max < arr[index] && max != arr[index]) {
          max = arr[index];     
        }  
   }
        return max;
    
}

//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)

array max in javascript

javascript array maximum