JAVASCRIPT

Javascript Check if number is even or odd

function solution(num) {
    return num % 2 === 0 ? 'Even' : 'Odd'
}

if odd js

function isEven(value) {
    return !(value % 2)
}

Even number function in javascript

function isEven(numbers) {
    if (numbers % 2 == 0) {
        return true;
    }
    return false;

}
var input = 22;
var result = isEven(input);
console.log(result)
//Outpur: true

javascript is number even or odd

// vanilla
function isEven(num) {
   return num % 2 == 0;
}

function isOdd(num) {
   return Math.abs(num % 2) == 1;
}

// ES6
const isEven = num => ((num % 2) == 0);

//bitwise AND operator
const isOdd = function(num) { return num & 1; };
const isEven  = function(num) { return !( num & 1 ); };

Odd number function in javascript

function isOdd(numbers) {
    if (numbers % 2 != 0) {
        return true;
    }
    return false;

}
var input = 343;
var result = isOdd(input);
console.log(result)
//Outpur: true

even or odd in javascript

const isEven = (num) => num % 2 === 0;
console.log(isEven(5));// falseconsole.log(isEven(4));// true

odd or even js

for(let count =0; count<=100;count++){
 count%2==0? console.log(`${count} is even`):console.log(`${count} is odd`);
 ;
}

odd even javascript

var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];
    
    for (var i = 0; i < arr.length; i++) {
      if (arr[i]%2 == 0) {
        arr.push(arr.splice(i, 1)[0]);
      }
    }
    
    console.log(arr);

odd number is javascript

let arr = [1,2,3,4,5,6,7,8,9,10,11,12]

let odds = arr.filter(n => n%2)

console.log(odds)
 Run code snippetHide results

is odd javascript

const isOdd = n => !!(n & 1)

odd and even in javascript

const OddorEven = (num)=>num&1?"odd":"even";

javascript even number

let isEven = (n) => !(n&1);