JAVASCRIPT

max value in array javascript

// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });

// For arrays with relatively few elements you can use apply: 
const max = Math.max.apply(null, arr);

// or spread operator:
const max = Math.max(...arr);

js get max value in an array

const myArray = [1, 14, 32, 7];

const maxValue = Math.max(...myArray);

console.log(maxValue); // 32

javascript max array

var values = [3, 5, 6, 1, 4];

var max_value = Math.max(...values); //6
var min_value = Math.min(...values); //1

find highest value in array javascript

const array = [10, 2, 33, 4, 5];

console.log(Math.max(...array)
)

Find the maximum number of an array js

var arr = [1, 2, 3];
var max = arr.reduce(function(a, b) {
  return Math.max(a, b);
});

js find all max number indexes in array

const arr = [0,1,4,3,4];
const max = Math.max(...arr);
let res = [];
arr.forEach((item, index) => item === max ? res.push(index): null);
console.log(res);

Find the maximum number of an array js

function getMaxOfArray(numArray) {
    return Math.max.apply(null, numArray);
}

how to find max in min in an array

 public static void main(String[] args) {

        int[] xr = {2, 4, 1, 3, 7, 5, 6, 10, 8, 9};

        //find maximum value
        int max = xr[0];
        for (int i = 0; i < xr.length; i++) {
            if (xr[i] > max) {
                max = xr[i];
            }
        }

        //find minimum value
        int min=xr[0];
        for (int i = 0; i <xr.length ; i++) {
            if (xr[i]<min){
                min=xr[i];
            }
        }

        System.out.println("max: "+max);
        System.out.println("min: "+min);
    }

javascript max array

Math.max(1, 2, 3)    // 3
Math.min(1, 2, 3)    // 1

var nums = [1, 2, 3]
Math.min(...nums)    // 1
Math.max(...nums)    // 3

max value from array in javascript

// For regular arrays:
var max = Math.max(...arrayOfNumbers);

// For arrays with tens of thousands of items: 
let max = testArray[0];  //here we have considered max to the first element because we don't know which is max yet.
for (let i = 1; i < testArrayLength; ++i) { 
  if (testArray[i] > max) {  //in each iteration it will compare if the value is greater than the current considered value (we just considered first element)
    max = testArray[i]; //in the above iteration if the testArray find value/element greater than max then this new max value will be considered as Max (this will happen until the max value found).
  }
}

find max and min value in array javascript

var numbers = [1, 2, 3, 4];
Math.max(...numbers) // 4
Math.min(...numbers) // 1

js max array

Math.min(...arr) // min
Math.max(...arr) // max

Max Number from Array in JS

function arrayMax(array) {
  return array.reduce(function(a, b) {
    return Math.max(a, b);
  });
}

function arrayMin(array) {
  return array.reduce(function(a, b) {
    return Math.min(a, b);
  });
}

find max value in array javascript

// find maximum value of array in javascript
// array reduce method
const arr = [49,2,71,5,38,96];
const max = arr.reduce((a, b) => Math.max(a, b));
console.log(max); // 96

// math.max apply method
const max_ = Math.max.apply(null, arr);
console.log(max_); // 96

// or math.max spread operator method
const max__ = Math.max(...arr);
console.log(max__); // 96

how to return the max and min of an array in javascript

function minMax(arr) {
  return [Math.min(...arr), Math.max(...arr)];
}

js max array

Math.max(...array);

js max with array

var myArray = [5, 10, 50];
Math.max(myArray);    // Error: NaN
Math.max.apply(Math, myArray);    // 50

how to find max number in array javascript

const array1 = [1, 3, 2];
console.log(Math.max(...array1));

max element in array

int max;
max=INT_MIN;

for(int i=0;i<ar.length();i++){
	if(ar[i]>max){
    	max=ar[i];
    }

       

js how to find max value in an array

(function () {
  const arr = [23, 65, 3, 19, 42, 74, 56, 8, 88];

  function findMaxArrValue(arr) {
    if (arr.length) {
      let max = -Infinity;

      for (let num of arr) {
        max = num > max ? num : max;
      }
      return max;
    }
    return 0; // or any value what you need
  }

  console.log(findMaxArrValue(arr)); // => 88
})();

Math max with array js

var nums = [1, 2, 3]
Math.min.apply(Math, nums)    // 1
Math.max.apply(Math, nums)    // 3
Math.min.apply(null, nums)    // 1
Math.max.apply(null, nums)    // 3

get max number in array

console.log(arrayNumbers.sort((a, b) => a - b ));

find the maximum no. in array js

function findMaxArrValue(numbers) {
  let max = 0;
  numbers.forEach((number) => {if (number > max) {max = number}});
  return max;
}

console.log(findMaxArrValue([23, 69, 55, 31, 75, 100, 82]));
//Output 100

find the max number in an array js

var myPersons__ = document.querySelectorAll('.avtrlnk');
var maxId__ = [];
    
	for(var x = 0; x < myPersons__.length; ++x) {
		maxId__[x] = myPersons__[x].value;
	}
	myPersons__ = parseInt(maxId__.sort()[x-1]) + 1;

max value in an array

console.log(Math.max(1, 3, 2));
// expected output: 3

console.log(Math.max(-1, -3, -2));
// expected output: -1

const array1 = [1, 3, 2];

console.log(Math.max(...array1));
// expected output: 3

array max value

const findMax = (arr)=>{
    let max = 0 ;
   for (let index = 0; index < arr.length; index++) {
        if (max < arr[index] && max != arr[index]) {
          max = arr[index];     
        }  
   }
        return max;
    
}

//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)

array max in javascript

javascript array maximum

js max number in array mdn

// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });

// For arrays with relatively few elements you can use apply: 
const max = Math.max.apply(null, arr);

// or spread operator:
const max = Math.max(...arr);

Find the maximum number of an array js

Math.max(10, 20);   //  20
Math.max(-10, -20); // -10
Math.max(-10, 20);  //  20