JAVASCRIPT

sum of all numbers in an array javascript

const arrSum = arr => arr.reduce((a,b) => a + b, 0)

sum of numbers in array with javascript

const sumNums = (arr)=>{
    let sum=0;
    for (let t = 0; t < arr.length; t++) {
        if(typeof arr[t] == "number" ){

           sum = sum + arr[t] ;
        }
        
    }
    return sum;
}

//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)

js sum of int in array

const sum = [1, 2, 3].reduce((partialSum, a) => partialSum + a, 0);
console.log(sum); // 6

sum values in array javascript

const num = [1, 3, 1, 1] 
const reducer = (accumulator, currentValue) => accumulator + currentValue;
const sum = num.reduce(reducer);
console.log(sum)
// (1+3+1+1) = 6

sum of array of number

const sum = [1, 2, 3].reduce((partialSum, a) => partialSum + a, 0);
console.log(sum); // 6
 Run code snippet

how to find the sum of array using JavaScript

// If you do not want to use array.reduece you can itereate through the array and then get the solution.
const  getSum = (arr)=>{
  let sum = 0;
  for(key of arr){
    sum += key
  }
  return sum
}

sum of an array

const sum = (...args) => args.reduce((a, b) => a + b, 0);
console.log(sum(1,2,3)); // returns 6

array values sum

$a = array(5,15,25);
echo array_sum($a);

sum of arrays

/**
 * C program to find sum of all elements of array
 */

#include <stdio.h>
#define MAX_SIZE 100

int main()
{
    int arr[MAX_SIZE];
    int i, n, sum=0;

    /* Input size of the array */
    printf("Enter size of the array: ");
    scanf("%d", &n);

    /* Input elements in array */
    printf("Enter %d elements in the array: ", n);
    for(i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);

        // Add each array element to sum
        sum += arr[i];
    }

    printf("Sum of all elements of array = %d", sum);

    return 0;
}

sum of arrays

/**
 * C program to find sum of all elements of array 
 */

#include <stdio.h>
#define MAX_SIZE 100

int main()
{
    int arr[MAX_SIZE];
    int i, n, sum=0;

    /* Input size of the array */
    printf("Enter size of the array: ");
    scanf("%d", &n);

    /* Input elements in array */
    printf("Enter %d elements in the array: ", n);
    for(i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);
    }

    /*
     * Add each array element to sum
     */
    for(i=0; i<n; i++)
    {
        sum = sum + arr[i];
    }


    printf("Sum of all elements of array = %d", sum);

    return 0;
}

how to find sum of array

//C++
int arr[5]={1,2,3,4,5};
int sum=0;
for(int i=0; i<5; i++){sum+=arr[i];}
cout<<sum;

sum of array

int sumofarr(int *a, int n) {
	if (n>1)
        return a[n-1]+sumofarr(a, n-1);
    return a[0];
}

return the sum of an array

[0, 1, 2, 3, 4].reduce(function(accumulateur, valeurCourante, index, array){
  return accumulateur + valeurCourante;
}, 10);

sum of array value

$total = 0;
foreach ($products as $product) {
    $subtotal = $product['price']*$product['quantity'];
    $total += $subtotal;
}

echo $total;

sum of all numbers in an array javascript

const arrSum = arr => arr.reduce((a,b) => a + b, 0)

sum of numbers in array with javascript

const sumNums = (arr)=>{
    let sum=0;
    for (let t = 0; t < arr.length; t++) {
        if(typeof arr[t] == "number" ){

           sum = sum + arr[t] ;
        }
        
    }
    return sum;
}

//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)

js sum of int in array

const sum = [1, 2, 3].reduce((partialSum, a) => partialSum + a, 0);
console.log(sum); // 6

sum values in array javascript

const num = [1, 3, 1, 1] 
const reducer = (accumulator, currentValue) => accumulator + currentValue;
const sum = num.reduce(reducer);
console.log(sum)
// (1+3+1+1) = 6

sum of array of number

const sum = [1, 2, 3].reduce((partialSum, a) => partialSum + a, 0);
console.log(sum); // 6
 Run code snippet

how to find the sum of array using JavaScript

// If you do not want to use array.reduece you can itereate through the array and then get the solution.
const  getSum = (arr)=>{
  let sum = 0;
  for(key of arr){
    sum += key
  }
  return sum
}

sum of an array

const sum = (...args) => args.reduce((a, b) => a + b, 0);
console.log(sum(1,2,3)); // returns 6

array values sum

$a = array(5,15,25);
echo array_sum($a);

sum of arrays

/**
 * C program to find sum of all elements of array
 */

#include <stdio.h>
#define MAX_SIZE 100

int main()
{
    int arr[MAX_SIZE];
    int i, n, sum=0;

    /* Input size of the array */
    printf("Enter size of the array: ");
    scanf("%d", &n);

    /* Input elements in array */
    printf("Enter %d elements in the array: ", n);
    for(i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);

        // Add each array element to sum
        sum += arr[i];
    }

    printf("Sum of all elements of array = %d", sum);

    return 0;
}

sum of arrays

/**
 * C program to find sum of all elements of array 
 */

#include <stdio.h>
#define MAX_SIZE 100

int main()
{
    int arr[MAX_SIZE];
    int i, n, sum=0;

    /* Input size of the array */
    printf("Enter size of the array: ");
    scanf("%d", &n);

    /* Input elements in array */
    printf("Enter %d elements in the array: ", n);
    for(i=0; i<n; i++)
    {
        scanf("%d", &arr[i]);
    }

    /*
     * Add each array element to sum
     */
    for(i=0; i<n; i++)
    {
        sum = sum + arr[i];
    }


    printf("Sum of all elements of array = %d", sum);

    return 0;
}

how to find sum of array

//C++
int arr[5]={1,2,3,4,5};
int sum=0;
for(int i=0; i<5; i++){sum+=arr[i];}
cout<<sum;

sum of array

int sumofarr(int *a, int n) {
	if (n>1)
        return a[n-1]+sumofarr(a, n-1);
    return a[0];
}

return the sum of an array

[0, 1, 2, 3, 4].reduce(function(accumulateur, valeurCourante, index, array){
  return accumulateur + valeurCourante;
}, 10);

sum of array value

$total = 0;
foreach ($products as $product) {
    $subtotal = $product['price']*$product['quantity'];
    $total += $subtotal;
}

echo $total;