DekGenius.com
JAVASCRIPT
javascript array unique values
var arr = [55, 44, 65,1,2,3,3,34,5];
var unique = [...new Set(arr)]
//just var unique = new Set(arr) wont be an array
how to find unique elements in array in javascript
let a = ["1", "1", "2", "3", "3", "1"];
let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
console.log(unique);
javascript find unique values in array
// usage example:
var myArray = ['a', 1, 'a', 2, '1'];
var unique = myArray.filter((v, i, a) => a.indexOf(v) === i);
// unique is ['a', 1, 2, '1']
array unique values javascript
const myArray = ['a', 1, 'a', 2, '1'];
const unique = [...new Set(myArray)]; // ['a', 1, 2, '1']
unique values in array javascript
let uniqueItems = [...new Set(items)]
get unique array javascript
// one liner solution to get a unique array by object id
[{_id: 10},{_id: 20}, {_id: 20}].filter((item, i, ar) => ar.findIndex(each => each._id === item._id) === i)
unique element in array
const unique = (value, index, self) => {
return self.indexOf(value) === index
}
const ages = [26, 27, 26, 26, 28, 28, 29, 29, 30]
const uniqueAges = ages.filter(unique)
console.log(uniqueAges)
unique array
<?php
// app.php
$data = [19, 21, 19, 21, 46, 21, 29, 21, 18];
print_r(array_unique($data));
find unique value on array
const a = [1, 9, 2, 2, 3, 4, 1, 7, 8, 0, 9, 0, 1, 5, 3];
const b = a.filter(function (item, index, array) {
return array.lastIndexOf(item) === index; // this will return the unique elements
});
unique array in javascript
const uniqueArr = [...new Set(arr)]
find unique elements in array
const arr1=[1,2,3,4,5,5];
const unique = arr1.filter((item, index, array)=>
array.indexOf(item)===index
)
console.log(unique)
array with unique values javascript
let uniqueItems = [...new Set(items)]
how to find unique values in an array in js using function
// app.js
Array.prototype.unique = function() {
let arr = [];
for(let i = 0; i < this.length; i++) {
if(!arr.includes(this[i])) {
arr.push(this[i]);
}
}
return arr;
}
const ages = [26, 27, 26, 26, 28, 28, 29, 29, 30]
const uniqueAges = ages.unique()
console.log(uniqueAges)
unique array
const array = [2,5,7,5,6,4,2,4,5,8,412,477,36,8,2,34,7]
const generateUniqueArray => arr => [... new Set(arr)]
const result = generateUniqueArray(array)
console.log(result) // [ 2, 5, 7, 6, 4, 8, 412, 477, 36, 34]
// With love @kouqhar
javascript unique array
const mySet = new Set([1,2])
const additionalSet = [5,2,6]
mySet = new Set([...mySet, ...additionalSet]) // {1,2,5,6}
array = [...new Set([...mySet, ...additionalSet])] // [1,2,5,6]
Finding unique number in the array
class Solution {
public int singleNumber(int[] nums) {
int n=0;
for(int i:nums){
n=n^i;
}
return n;
}
}
find unique elements in array
const arr[1,2,3,4,4,5,5]
console.log(...new Set(arr))
© 2022 Copyright:
DekGenius.com