$stmt = $db->prepare("...");
$stmt->execute();
$id = $db->lastInsertId();
Beware of lastInsertId() when working with transactions in mysql. The following code returns 0 instead of the insert id.
<?php
try {
$dbh = new PDO('mysql:host=localhost;dbname=test', 'username', 'password');
$stmt = $dbh->prepare("INSERT INTO test (name, email) VALUES(?,?)");
try {
$dbh->beginTransaction();
$tmt->execute( array('user', 'user@example.com'));
$dbh->commit();
print $dbh->lastInsertId();
} catch(PDOExecption $e) {
$dbh->rollback();
print "Error!: " . $e->getMessage() . "</br>";
}
} catch( PDOExecption $e ) {
print "Error!: " . $e->getMessage() . "</br>";
}
?>
When no exception is thrown, lastInsertId returns 0. However, if lastInsertId is called before calling commit, the right id is returned.
$(document).ready(function(){
$.ajax({ url: "database/update.html",
context: document.body,
success: function(){
alert("done");
}});
});