PHP

php date + 1 year

$today =date('Y-m-d');
$expiryDate=date('Y-m-d H:i:s', strtotime('+1 year', strtotime($today)) );

php grab year from date

$year = date("y",strtotime($mydate));

year in php

date('Y')

php year from date

echo date('Y', $date);

php get date from day of year

// This should get you a DateTime object from the date and year.
function getDateFromDay($dayOfYear, $year) {
  $date = DateTime::createFromFormat('z Y', strval($dayOfYear) . ' ' . strval($year));
  return $date;
}

// This should get you the day of the year and the year in a string.
date('z Y', strtotime('21 oct 2012'));