PYTHON

is prime python

def is_prime(n):
    for i in range(2,int(n**0.5)+1):
        if n%i==0:
            return False
    return True

is prime python

import math
def isPrimeNumber(n):
    if (n < 2):
        return False;
    sq = int(math.sqrt(n))
    for i in range(2, sq + 1):
        if (n % i == 0):
            return False
    return True

python prime check

def isPrime(n):
  if n<2:		#1, 0 and all negative numbers are not prime
    return False
  elif n==2:	#2 is prime but cannot be calculated with the formula below becuase of the range function
    return True
  else:
    for i in range(2, n):
      if (n % i) == 0:	#if you can precisely divide a number by another number, it is not prime
        return False
    return True			#if the progam dont return False and arrives here, it means it has checked all the numebrs smaller than n and nono of them divides n. So n is prime

python is prime

from sympy import isprime
isprime(23)

Python code for checking if a number is a prime number

for i in range(2, 20):
    for x in range(2, i):
        if i % x == 0:
            break
    else:
        print(i, "is a prime number")

how to see if a number is prime in python

def is_prime(n: int) -> bool:
    """Primality test using 6k+-1 optimization."""
    if n <= 3:
        return n > 1
    if n % 2 == 0 or n % 3 == 0:
        return False
    i = 5
    while i ** 2 <= n:
        if n % i == 0 or n % (i + 2) == 0:
            return False
        i += 6
    return True

check for prime in python

def is_prime(n: int) -> bool:
    """Primality test using 6k+-1 optimization."""
    import math
    if n <= 3:
        return n > 1
    if n % 2 == 0 or n % 3 == 0:
        return False
    i = 5
    while i <= math.sqrt(n):
        if n % i == 0 or n % (i + 2) == 0:
            return False
        i += 6
    return True

check if number is prime python

def check_if_prime():
    number = int(input("Enter number: "))
    
    prime_lists = [1,2,3]
    
    divisible_by = []
    if number in prime_lists:
        return divisible_by
    
    if number==0:
        return None
    
    for i in range(2,number):
        
        if number%i==0:
            divisible_by.append(i)
            
    return divisible_by
        
    
check_if_prime()

python is prime

from math import sqrt, floor;

def is_prime(num):
    if num < 2: return False;
    if num == 2: return True;
    if num % 2 == 0: return False;
    for i in range(3,floor(sqrt(num))+1,2):
        if num % i == 0: return False;
    return True;

is prime python

def is_prime(n):
  return bool(n&1)