PYTHON

how to find duplicate numbers in list in python

l=[1,2,3,4,5,2,3,4,7,9,5]
l1=[]
for i in l:
    if i not in l1:
        l1.append(i)
    else:
        print(i,end=' ')

find duplicates in python list

names = ['name1', 'name2', 'name3', 'name2']
set([name for name in names if names.count(name) > 1])

how to check if there are duplicates in a list python

>>> your_list = ['one', 'two', 'one']
>>> len(your_list) != len(set(your_list))
True

python efficiently find duplicates in list

from collections import Counter

def get_duplicates(array):
    c = Counter(array)
    return [k for k in c if c[k] > 1]

find duplicated entries present in a list

How to Find Out the Duplicated Values Present In a List:

some_list=['a','b','c','b','d','m','n','n']

 my_list=sorted(some_list)
 
duplicates=[]
for i in my_list:
     if my_list.count(i)>1:
         if i not in duplicates:
             duplicates.append(i)
 
print(duplicates)

Check if there are duplicates in list

list= ["a", "a", "b", "c", "d", "e", "f"] 

 
for x in range(0, len(list)-1):
    if(list[x]==list[x+1]):
        print("Duplicate found!");
    
    

print(list) 

check list for duplicate values python

a = [1,2,3,2,1,5,6,5,5,5]

import collections
print([item for item, count in collections.Counter(a).items() if count > 1])

## [1, 2, 5]

how to check the duplicate item in list

thelist = [1, 2, 3, 4, 4, 5, 5, 6, 1]
 
print(len(thelist) != len(set(thelist)))