PYTHON

difference between two dictionaries python

value = { k : second_dict[k] for k in set(second_dict) - set(first_dict) }

compare two dictionaries in python

def dict_compare(d1, d2):
    d1_keys = set(d1.keys())
    d2_keys = set(d2.keys())
    shared_keys = d1_keys.intersection(d2_keys)
    added = d1_keys - d2_keys
    removed = d2_keys - d1_keys
    modified = {o : (d1[o], d2[o]) for o in shared_keys if d1[o] != d2[o]}
    same = set(o for o in shared_keys if d1[o] == d2[o])
    return added, removed, modified, same

x = dict(a=1, b=2)
y = dict(a=2, b=2)
added, removed, modified, same = dict_compare(x, y)

how to compare values in dictionary with same key python

if (key in dictionary2 and dictionary1[key] == dictionary2[key]):

comparing list and dictionary python

# Comparing lists and dictionaries
# We create an empty list and an empty dictionary
lst = []                    # Other way is lst = list()
dictionary = {}             # Other way is dictionary = dict()
# adding items to the list
lst.append(25)
lst.append(34)
print(lst)                  # Output: [25, 34]
# adding values to a dictionary using keys
dictionary['first'] = 25
dictionary['second'] = 34
print(dictionary)           # Output: {'first': 25, 'second': 34}
# Change an item using index in list
lst[0] = 23
print(lst)                  # Output: [23, 34]
# Change a value using key in dictionary
dictionary['first'] = 34
print(dictionary)           # Output: {'first': 34, 'second': 34}