PYTHON

value count a list python

from collections import Counter
z = ['blue', 'red', 'blue', 'yellow', 'blue', 'red']
Counter(z)
>>> Counter({'blue': 3, 'red': 2, 'yellow': 1})

count items in list

>>> from collections import Counter
>>> mylist = ["Bob", "Mike", "Bob", "Mike", "Mike", "Mike", "Bob"]
>>> Counter(mylist)
Counter({'Mike': 4, 'Bob': 3})

count the element in list

from collections import Counter
 
thelist = [1, 4, 2, 3, 5, 4, 5, 6, 7, 8, 1, 3, 4, 5, 9, 10, 11]
c = Counter(thelist)
print(c.most_common(1))

python find the number of elements in a list

list1 = [2,3,4,3,10,3,5,6,3]
elm_count = list1.count(3)
print('The count of element: 3 is ', elm_count)

count item in list python

list.count(element)

count number of each item in list python

word_counter = {}
book_title =  ['great', 'expectations','the', 'adventures', 'of', 'sherlock','holmes','the','great','gasby','hamlet','adventures','of','huckleberry','fin']

for word in book_title:
    if word not in word_counter:
        word_counter[word] = 1
    else:
        word_counter[word] += 1

print(word_counter)

# output - {'great': 2, 'expectations': 1, 'the': 2, 'adventures': 2, 'of': 2, 'sherlock': 1, 'holmes': 1, 'gasby': 1, 'hamlet': 1, 'huckleberry': 1, 'fin': 1}

python count items in list

from collections import Counter
a = [1,2,3,4,5,6,6,6,5,5]
Counter(a)

number of elements in list in python

# List of strings
listOfElems = ['Hello', 'Ok', 'is', 'Ok', 'test', 'this', 'is', 'a', 'test']
len(s)

check number of elements in list python

>>> len([1,2,3])
3

count number items in list python

mylist = ["abc", "def", "ghi", "jkl", "mno", "pqr"]

print(len(mylist))

# output 6

Count elements in list Python

List = ["Elephant", "Snake", "Penguin"]

print(len(List))

#	With the 'len' function Python counts the amount of elements 
#	in a list (The length of the list).

count number of element in list

"""Find all occurrences of element in list"""

# If you simply want find how many times an element appears
# use the built-in function count()
def find_occur(lst, item):
	return lst.count(item)

# Test -----------------------------------------------------------
print(find_occur([None, None, 1, 2, 3, 4, 5], None)) # 2

# If you wanna find where they occur instead
# - This returns the indices where element is found within a list

def find(lst, item):
    return [i for (i, x) in enumerate(lst) if x == item]

# Test Code ------------------------------------------------------
from random import randint, choice
lst = [randint(0, 99) for x in range(10)] # random lst
item = choice(lst) # item to find
found = find(lst, item) # lst of where item is found at
print(f"lst: {lst}",
      f"item: {item}",
      f"found: {found}",
      sep = "
")

python number of elements in a list

list_a = ["Hello", 2, 15, "World", 34] #just the array

number_of_elements = len(list_a)

print("Number of elements in the list: ", number_of_elements)

List Count Elements

a = ["more", 4, 6]
print(len(a))
# prints 3

counting the number of items in a list with get in python

counts = {}
names_list = ['John', 'Anne', 'Sam', 'Li', 'Sam', 'John']
for name in names_list:
    counts[name] = counts.get(name,0) +1
print(counts)

python how to detect number of items in a list

# List of just integers
list_a = [12, 5, 91, 18]

# List of integers, floats, strings, booleans
list_b = [4, 1.2, "hello world", True]