PYTHON

how to find duplicate numbers in list in python

l=[1,2,3,4,5,2,3,4,7,9,5]
l1=[]
for i in l:
    if i not in l1:
        l1.append(i)
    else:
        print(i,end=' ')

find duplicates in python list

names = ['name1', 'name2', 'name3', 'name2']
set([name for name in names if names.count(name) > 1])

how to check if there are duplicates in a list python

>>> your_list = ['one', 'two', 'one']
>>> len(your_list) != len(set(your_list))
True

duplicate in list

thelist = [1, 2, 3, 4, 4, 5, 5, 6, 1]
 
 
def dup(x):
    duplicate = []
    unique = []
    for i in x:
        if i in unique:
            duplicate.append(i)
        else:
            unique.append(i)
    print("Duplicate values: ", duplicate)
    print("Unique Values: ", unique)
 
 
dup(thelist)

duplicate in list

thelist = [1, 2, 3, 4, 4, 5, 5, 6, 1]
 
 
def dup(x):
    duplicate = []
    unique = []
    for i in x:
        if i in unique:
            duplicate.append(i)
        else:
            unique.append(i)
    print("Duplicate values: ", duplicate)
    print("Unique Values: ", unique)
 
 
dup(thelist)

duplicates in python list

def findDuplicates(items):
    """ This function returns dict of duplicates items in Iterable
        and how much times it gets repeated in key value pair"""
    result = {}
    item = sorted(items)
    for i in item:
        if item.count(i) > 1:
            result.update({i: items.count(i)})
    return result
  
print(findDuplicates([1,2,3,4,3,4,2,7,4,7,8]))
# output will be {2: 2, 3: 2, 4: 3, 7: 2}

how to check the duplicate item in list

thelist = [1, 2, 3, 4, 4, 5, 5, 6, 1]
 
print(len(thelist) != len(set(thelist)))

how to duplicate a list in python

example = [1,2,3,4,5,6,7,8] #this is the list

for i in example:
  example.append(example[i])