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filter list dict

fl = list(filter(lambda x: x['first'] == 'Christian', dictlist))

# you can't use `.property` because this is a dictionary, not a object
fl[0]['last']
# returns Doppler
Comment

python filter a dictionary

d = dict(a=1, b=2, c=3, d=4, e=5)
print(d)
d1 = {x: d[x] for x in d.keys() if x not in ['a', 'b']}
print(d1)
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python filter list of dictionaries by value

dict_list = [{'a': 1, 'b': 2}, {'b': 1, 'c': 2}, {'c': 1, 'd': 2}]
filter_value = 2

[{k:v for k,v in d.items() if v == filter_value} for d in dict_list]
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python filter dictionary

dict
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filter dictionary python

friends = [
    {'name': 'Sam', 'gender': 'male', 'sport': 'Basketball'},
    {'name': 'Emily', 'gender': 'female', 'sport': 'Volleyball'}
]
# filter by column names
print([{key: friend[key] for key in friend.keys() if key in ["name", "sport"]} for friend in friends])
# filter by rows
print([a for a in friends if a["name"] in ["Sam"]])
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