PYTHON

FIND MISSING NUMBER IN AN ARRAY IN PYTHON

def get_missing_summatin(a):
  n = a[-1]
  total = n*(n+1)//2
  summation = 0
  summation = sum(a)
  result = total-summation
  print(result)

a = [1,2,3,5,6,7]
get_missing_summatin(a)

find missing number in the array

// Java program to find missing Number
 
import java.util.*;
import java.util.Arrays;
 
class GFG {
 
    // Function to find the missing number
    public static int getMissingNo(int[] nums, int n)
    {
        int sum = ((n + 1) * (n + 2)) / 2;
        for (int i = 0; i < n; i++)
            sum -= nums[i];
        return sum;
    }
 
    // Driver code
    public static void main(String[] args)
    {
        int[] arr = { 1, 2, 3, 5 };
        int N = arr.length;
        System.out.println(getMissingNo(arr, N));
    }
}

how to find missing number in array

const findMissing = num => {
  const max = Math.max(...num); // Will find highest number
  const min = Math.min(...num); // Will find lowest number
  const missing = []

  for(let i=min; i<= max; i++) {
    if(!num.includes(i)) { // Checking whether i(current value) present in num(argument)
      missing.push(i); // Adding numbers which are not in num(argument) array
    }
  }
  return missing;
}

findMissing([1,10,5,41,35,26,2,15,34,44,12,46,49,50,14, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 27,]);

missing number in array

public class Solution 
{
    public int[] FindErrorNums(int[] nums) 
    =>nums.Concat(Enumerable.Range(1, nums.Length))
    .GroupBy(x=>x).Where(x=>x.Count()==1)
    .Select(x=>x.Key).ToArray();
}