Python

>>> ["foo", "bar", "baz"].index("bar")
1

["foo", "bar", "baz"].index("bar")

# To get value from index in a list:
x = ["Foo", "Bar", "Roblox"]

print(x[0]) # Output: Foo

PREVIOUS	NEXT

Code Example
Python :: variables and data types in python
Python :: drop column of datfame
Python :: Python RegEx Split – re.split()
Python :: inverse mask python
Python :: numpy array deepcopy
Python :: python how to print something at a specific place
Python :: download unsplash images python
Python :: Reverse an string Using Extended Slice Syntax in Python
Python :: table in sqlite python
Python :: cite pandas python
Python :: python obfuscator github
Python :: get coordinates in xarray
Python :: axios django post
Python :: sort python
Python :: latest version of python
Python :: python merge dict
Python :: multiplication of two or more numbers in python
Python :: how to plot stacked bar chart from grouped data pandas
Python :: making ckeditor django responsive
Python :: csv manipulation python
Python :: Disctionary to Array
Python :: Drop multiple columns with their index
Python :: python find first occurrence in list
Python :: python palindrome check
Python :: python update header row
Python :: WARNING: This is a development server
Python :: python sys
Python :: super title python
Python :: brute force string matching algorithm in python
Python :: pandas sub columns