default_data = {'item1': 1,
'item2': 2,
}
default_data.update({'item3': 3})
# or
default_data['item3'] = 3
# to add key-value pairs to a dictionary:
d1 = {
"1" : 1,
"2" : 2,
"3" : 3
} # Define the dictionary
d1["4"] = 4 # Add key-value pair "4" is key and 4 is value
print(d1) # will return updated dictionary
testing1={'one':1,'two':2}
''' update() is the method of dict() merges another dict into existing ones '''
''' it replaces the keys of exisiting ones with the the new ones '''
testing1.update({'two':3,'noice':69})
print(testing1) """ {'one':1,'two':3,'noice':69} """
d = {'a': 1, 'b': 2}
print(d)
d['a'] = 100 # existing key, so overwrite
d['c'] = 3 # new key, so add
d['d'] = 4
print(d)
>>> d1 = {1: 1, 2: 2}
>>> d2 = {2: 'ha!', 3: 3}
>>> d1.update(d2)
>>> d1
{1: 1, 2: 'ha!', 3: 3}
d = {1:2}
d.update({2: 4})
print(d) # {1: 2, 2: 4}
dict = {1 : 'one', 2 : 'two'}
# Print out the dict
print(dict)
# Add something to it
dict[3] = 'three'
# Print it out to see it has changed
print(dict)
test={'item1': 1,
'item2': 2,
}
default_data = test
default_data.update({'item3': 3})
# or
default_data['item3'] = 3
from collections import defaultdict
dates_dict = defaultdict(list)
for key, date in cur:
dates_dict[key].append(date)
# This automatically creates a new element where
# Your key = key, The value you want to input = value
dictionary_name[key] = value