PYTHON

how to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

how to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))  

odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

how to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

how to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))
     

wap in python to check a number is odd or even

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
  print(num ,"is even number
")  
#CODE BY VENOM STONE
else:  
  print(num,"is Odd number
")
#CODE BY VENOM STONE

Python program to check whether a number is even or odd

a = int(input("Enter the number to find odd or even "))
if (a % 2) == 0:
print("{0} is Even".format(a))
else:
print("{0} is Odd".format(a))

python even or odd

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

Python Code for Checking if a number is an Odd number

count2 = 0
for odd_number in range(1, 20):
    if odd_number % 2 != 0:
        count2 += 1
        print(odd_number)
print(f"we have {count2} odd numbers")

fastest way to check odd or even in python

>>> def isodd(num):
        return num & 1 and True or False

>>> isodd(10)
False
>>> isodd(9)
True