PYTHON

python get index of substring in liast

index = [idx for idx, s in enumerate(l) if 'tiger' in s][0]

find the index of a character in a string python

my_var = 'mummy'. #Find the position of 'm'

#Using find - find returns the index for the first instance from the left.
my_var.find('m')
# Output: 0

#Using rfind - rfind returns the index for the first instance from the right.
my_var.rfind('m')
# Output: 3
# With find() and rfind(), when substring is not found, it returns -1.

#NB: You can use index() and rindex(). In this case, when the substring is not
# found, it raises an exception.

python index of string

string = "Hello World"
string_slice = string[1:10] # "ello Worl" (index 1 up to 10)
string_last_chars = string[-5:] # "World" (5th index from last to the end)
H = string[0] # "H"

python get index of substring in liast

def index_containing_substring(the_list, substring):
    for i, s in enumerate(the_list):
        if substring in s:
              return i
    return -1

how to find the indexes of a substring in a string in python

import re
# matches_position_start will be a list of starting index positions
matches_start = re.finditer(word.lower(), string.lower())
matches_position_start = [match.start() for match in matches_start]

# matches_position_end will be a list of ending index positions
matches_end = re.finditer(word.lower(), string.lower())
matches_position_end = [match.end() for match in matches_end]