PYTHON

if in lambda function python

lambda x: True if x % 2 == 0 else False

lambda function with if elif else python

lambda <args> : <return Value> if <condition> else ( <return value> if <condition> else <return value>)
lambda x: x*10 if x<2 else (x**2 if x<4 else x+10)

how to use if else in lambda python

lambda <arguments> : <Return Value if condition is True> if <condition> else <Return Value if condition is False>
lambda x : True if (x > 10 and x < 20) else False

apply lambda with if

df['new column name'] = df['column name'].apply(lambda x: 'value if condition is met' if x condition else 'value if condition is not met')

lambda function if else in python

# Lambda function with if-else
square = lambda x : x*x if(x > 0) else None
 
print(square(4))

python lambda function if else

# Think of the lambda function as defining a REALLY small function without 
# a name.

# EXAMPLE #
lis = [2, 4, 6, 8]
output = lambda [parameter] : return True if [parameter] in lis else return False
print(output[4])

lambda function if else in python

# Lambda function with if-else
square = lambda x : x*x if(x > 0) else None
 
print(square(4))

if condition in python lambda

func = lambda element: (expression and DoSomething) or DoSomethingIfExpressionIsFalse