PYTHON

index of sorted list python

vals = numpy.array([2,3,1,4,5])
sort_index = numpy.argsort(vals)

>>> sort_index
array([2, 0, 1, 3, 4])

How to sort and get index of sorted list in python

import numpy
# example list : [9, 3, 1, 5, 88, 22, 99] 
# make the list
my_list = numpy.array([9, 3, 1, 5, 88, 22, 99])

# for increasing order
# indexing 
index=numpy.argsort(my_list)

# sorting 
inc_list = sorted(my_list, reverse=False) 

print(inc_list,index)


# for decreasing order
# indexing 
index=numpy.argsort(-my_list)

# sorting 
dec_list = sorted(my_list, reverse=True) 

print(dec_list,index)