PYTHON

leap year algorithm

def isLeapYear (year):
    if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
		true
    else:
    	false

leap year algorithm

if year % 4 == 0:
  if year % 100 == 0:
    if year % 400 == 0:
      print("leap year")
    else:
      print("not a leap year")
  else:
    print("leap year")
else:
  print("not a leap year")

Leap year program

#include <stdio.h>

int main() {
   int year;
   year = 2016;

   if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
      printf("%d is a leap year", year);
   else
      printf("%d is not a leap year", year);

   return 0;
}