PYTHON

how to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

odd or even in python

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")

odd or even python

num = int(input("Number: "))
mod = num % 2
if mod == 0:
    print(f"{num} is even")
else:
    print(f"{num} is odd")

finding odd even python

number = int(input("Write a number:- "))
if number%2 == 0:
    print("Even number")
else:
    print("odd number")

how to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

how to make a python program on odd and even

Number = int(input("Write any number:- "))
Opration = Number%2
if Opration == 0:
    print("it's odd number")
else:
    print("It's even number")

how to check if a number is even or odd in python

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))
     

python even or odd

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

python odd or even

n = int(input("Enter a number: "))
print(["even","odd"][n % 2])

Odd Or Even python

#! /urs/bin/env python3

# odd_or_even_function: this function will take in one integer parameter
# returning: print statements to console to inform user if the numbered entered
# was an even, odd, or divisible by 4.
def odd_or_even_function(num, check):

    # Calculating when num will be even but not divisible by 4
    if int(num) % 2 == 0 and int(num) % 4 != 0:
        print("The number " + str(num) + " is an even number")

    # Calculating when num will be divisible by 4
    elif int(num) % 2 == 0 and int(num) % 4 == 0:
        print("The number " + str(num) + " is an number divisible by 4.")

    # Calculating when num will be odd
    else:
        print("The number " + str(num) + " is an odd number")

    # Calculating when num can or can't divide evenly into check
    if int(num) % int(check) == 0:
        print(str(num) + " divides evenly by " + str(check))
    else:
        print(str(num) + " does not divide evenly by " + str(check))


def main():
    # information msg
    print("enter 'exit' to end program")
    print()

    # user_num = 1 so that we
    # can force user_num to enter while loop
    user_num = 1

    # user will be prompted to enter a number
    # this program will run until the user enters 'x'
    # then that will trigger the while loop
    # and program to close
    user_num = input("Enter a number: ")
    user_check = input("Enter a check number: ")
    while user_num != 'exit':
        odd_or_even_function(user_num, user_check)
        print()
        user_num = input("Enter a number: ")

    print("¡Hasta luego amigo!")


if __name__ == "__main__":
    main()

odd and even python

even = []
odd = []

for number in range(50, 71):
    if number % 2 == 0:
        odd.append(number)
    else:
        even.append(number)
    
print(f"Even: {even}
Odd: {odd}")

fastest way to check odd or even in python

>>> def isodd(num):
        return num & 1 and True or False

>>> isodd(10)
False
>>> isodd(9)
True

odd number in python

for tc in range(int(input())):
    a,b = map(int,input().split())
    x =  b//2 + (b%2)
    y =  a//2
    print("Case %d: %d"%(tc+1,x*x-y*y))
    
"""
Input:
2
1 10
2 10
Output:
Case 1: 25
Case 2: 24
"""