PYTHON

compare datetime string python

>>> from datetime import datetime as dt
>>> a = dt.strptime("10/12/13", "%m/%d/%y")
>>> b = dt.strptime("10/15/13", "%m/%d/%y")
>>> a > b
False
>>> a < b
True
>>>

python datetime compare date

datetime.datetime.strptime(str(datetime.date.today()), "%Y-%m-%d") >= datetime.datetime.strptime("2022-10-22", "%Y-%m-%d")

compare dates python

import datetime

today = datetime.date.today()

tomorow = today + datetime.timedelta(days=1)

1dayTimedelta = today - tomorow

result = 1dayTimedelta.total_seconds()
#the difference in seconds

compare two dates python

>>> from datetime import datetime, timedelta
>>> past = datetime.now() - timedelta(days=1)
>>> present = datetime.now()
>>> past < present
True
>>> datetime(3000, 1, 1) < present
False
>>> present - datetime(2000, 4, 4)
datetime.timedelta(4242, 75703, 762105)

compare two datetime in python

    jan_1_2020 = datetime.datetime(2020, 1, 1)
    dec_12_2020 = datetime.datetime(2020, 12, 12)

    if (jan_1_2020 < dec_12_2020):
        # ...


# More examples are at https://docs.python.org/3/library/datetime.html

compare dates in python

    jan_1_2020 = datetime.datetime(2020, 1, 1)
    dec_12_2020 = datetime.datetime(2020, 12, 12)

    if (jan_1_2020 < dec_12_2020):
        print("first datetime is less than the second")

python compare dates

    jan_1_2020 = datetime.datetime(2020, 1, 1)
    dec_12_2020 = datetime.datetime(2020, 12, 12)

    if (jan_1_2020 < dec_12_2020):
        print("first datetime is less than the second")

datatime, comparison of time python,compare time python

>>> a
datetime.datetime(2009, 12, 2, 10, 24, 34, 198130)
>>> b
datetime.datetime(2009, 12, 2, 10, 24, 36, 910128)
>>> a < b
True
>>> a > b
False
>>> a == a
True
>>> b == b
True
>>>

datatime, comparison of time python,compare time python

>>> this_morning = datetime.datetime(2009, 12, 2, 9, 30)
>>> last_night = datetime.datetime(2009, 12, 1, 20, 0)
>>> this_morning.time() < last_night.time()
True

phyton datetime comparison

# date in yyyy/mm/dd format
d1 = datetime.datetime(2018, 5, 3)
d2 = datetime.datetime(2018, 6, 1)
  
# Comparing the dates will return
# either True or False
print("d1 is greater than d2 : ", d1 > d2)

datatime, comparison of time python,compare time python

>>> import datetime
>>> now = datetime.datetime.now()
>>> today8am = now.replace(hour=8, minute=0, second=0, microsecond=0)
>>> now < today8am
True
>>> now == today8am
False
>>> now > today8am
False