PYTHON

python dictionary sort in descending order

dict = {"Python":750,"Java":950,"Ruby":700,"C++":200} 
 
sort_values = sorted(dict.items(), key=lambda y: y[1], reverse=True)

for i in sort_values:
	print(i[0], i[1])

how to sort a list of dictionary by value in descending order?

1. new_list = sorted(old_list, key=lambda k: k['key'], reverse=True)
/*use reverse=False for ascending order*/

ascending, descending dict

import operator
d = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
print('Original dictionary : ',d)
sorted_d = sorted(d.items(), key=operator.itemgetter(1))
print('Dictionary in ascending order by value : ',sorted_d)
sorted_d = dict( sorted(d.items(), key=operator.itemgetter(1),reverse=True))
print('Dictionary in descending order by value : ',sorted_d)