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extract zip file python

import zipfile
with zipfile.ZipFile(path_to_zip_file, 'r') as zip_ref:
    zip_ref.extractall(directory_to_extract_to)
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python unzip a zip

# app.py

from zipfile import ZipFile

with ZipFile('Mail3.zip', 'r') as zipObj:
   # Extract all the contents of zip file in different directory
   zipObj.extractall('temp')
   print('File is unzipped in temp folder')
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extract zip file in python zipfile

from zipfile import ZipFile
import zipfile

with ZipFile('test.zip') as myzip:
    with myzip.open('Roughwork/textfile.text') as myfile:
        print(myfile.readlines())Copy Code
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python extract zip file

from zipfile import ZipFile
import zipfile

myzip = ZipFile('test.zip') 
myzip.extract(member='Roughwork/pretify.html') 
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how to extract zip file using python

ZipFile.extractall(path=None, members=None, pwd=None)
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python extract zip file

import shutil
import zipfile

# base_name is the name of the zip file you want to create
# format is zip for zip file
# root_dir is the direct path of the folder or file you want to zip
shutil.make_archive(base_name='zip_file_name', format='zip', root_dir='data')

# read zip file from current path
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_ref:
   # create folder name extract_data in current directory with the extracted data
   zip_ref.extractall(path='extract_data')

# Extract a single file from a zip file
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_ref:
   # Extract a file name called secrets.dat
   zip_ref.extract(member='secrets.dat')
  
 # extract a list of filename within a zip file
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_obj:
    # Get list of files names in zip
    filenames = zip_obj.namelist()

    # Iterate over the list of file names in given list & print them
    for filename in filenames:
        print(filename)
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