PYTHON

python filter a dictionary

d = dict(a=1, b=2, c=3, d=4, e=5)
print(d)
d1 = {x: d[x] for x in d.keys() if x not in ['a', 'b']}
print(d1)

python filter dictionary by keys

# Basic syntax:
{key: your_dict[key] for key in your_dict.keys() and {'key_1', 'key_2'}}
# Where this uses list comprehension for dictionaries to make a new dictionary
#	with the keys that are found in the set

# Example usage:
your_dict = {'key_1': 1, 'key_2': 2, 'key_3': 3}
{key: your_dict[key] for key in your_dict.keys() and {'key_1', 'key_2'}}
--> {'key_1': 1, 'key_2': 2}

filter dict by list of keys python

dict_you_want = { your_key: old_dict[your_key] for your_key in your_keys }

filter dict with certain keys

>>> obj = { "a":1, "b":{"c":2,"d":3}}
>>> only(obj,["a","b.c"])
{'a': 1, 'b': {'c': 2}}

filter dict with certain keys

def only(object,keys):
    obj = {}
    for path in keys:
        paths = path.split(".")
        rec=''
        origin = object
        target = obj
        for key in paths:
            rec += key
            if key in target:
                target = target[key]
                origin = origin[key]
                rec += '.'
                continue
            if key in origin:
                if rec == path:
                    target[key] = origin[key]
                else:
                    target[key] = {}
                target = target[key]
                origin = origin[key]
                rec += '.'
            else:
                target[key] = None
                break
    return obj

python filter dictionary

dict

filter dictionary python

friends = [
    {'name': 'Sam', 'gender': 'male', 'sport': 'Basketball'},
    {'name': 'Emily', 'gender': 'female', 'sport': 'Volleyball'}
]
# filter by column names
print([{key: friend[key] for key in friend.keys() if key in ["name", "sport"]} for friend in friends])
# filter by rows
print([a for a in friends if a["name"] in ["Sam"]])