PYTHON

python last element in list

# To get the last element in a list you use -1 as position
bikes = ['trek', 'redline', 'giant']
bikes[-1]
# Output:
# 'giant'

python last element of list

print(list[-1])

last element of list python

list1 = ['a','b','c']
print(list1[-1])

last element in list py

l = [1,2,3,4,5]
last = l[len(l)-1]

python last item in list

some_list = [1,2,3]
some_list[-1] is the shortest and most Pythonic.
#output = 3

get every item but the last item of python list

x = [1, 2, 3, 4]

#same array, but the last item.
notLast = x[0:-1]

python last 3 list elements

array = ["a", "b", "c", "d"]

num_elements = 3
print(array[-num_elements:])

python last element of list

# to print the last item from a list
print(list[-1])

last element of list python

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

python list last element

my_list = ['red', 'blue', 'green']
# Get the last item with brute force using len
last_item = my_list[len(my_list) - 1]
# Remove the last item from the list using pop
last_item = my_list.pop() 
# Get the last item using negative indices *preferred & quickest method*
last_item = my_list[-1]
# Get the last item using iterable unpacking
*_, last_item = my_list

get last x elements of list python

# To get the last 2 elements in a list you use -2: as position
bikes = ['trek', 'redline', 'giant']
bikes = bikes[-2:]
# Output:
# ['redline', 'giant']

last element of python list

list1 = [1, 2, 3, 4, 5]
print(list1[len(list1)-1])
print(list1[-1])
print(list1.pop())

get last elements of list python

>>> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
>>> a
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
>>> a[-9:]
[4, 5, 6, 7, 8, 9, 10, 11, 12]

python last element of list

>>> list[-1:] # returns indexed value
    [3]
>>> list[-1]  # returns value
    3

Last element of list

bikes = ['trek', 'redline', 'giant']
bikes[-1]