>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter(lambda a: a != 2, x))
[1, 3, 3, 4]
new_list = filter(lambda x: x != [1,1], a)
rec1=[88,23,7,66,88,7,2,88,90]
def removes(lst,item):
rems= lst.count(item) # count number of times the item occurs e.g 7 appears twice
if not rems: # return if item does not occur in the list
return
for i in range(rems): #loop through the number occurrences
lst.remove(item) #remove each occurrence
removes(rec1,7)
def pop_x(arr, x):
return list(filter(lambda i: i != x, arr))
# Removes all int values(x) from list(arr), in python 3.