PYTHON

python set remove

s = {0, 1, 2}
s.discard(0)  
print(s)
{1, 2}

# discard() does not throw an exception if element not found
s.discard(0)

# remove() will throw
s.remove(0)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
KeyError: 0

remove an item from a set python

# it doesn't raise error if element doesn't exits in set

thisset = {1, 2,3}

thisset.discard(3)

print(thisset)

remove element form set in python

list1 = {1,2,3,4}
list1.remove(4)
print(list)
# {1,2,3}

remove an item from a set python

list.discard(item)

python remove to set

s = set()
s.remove(x)

set remove in python

# Creating an empty set
b = set()
print(type(b))

## Adding values to an empty set
b.add(4)
b.add(4)
b.add(5)
b.add(5) # Adding a value repeatedly does not changes a set
b.add((4, 5, 6))

## Accessing Elements
# b.add({4:5}) # Cannot add list or dictionary to sets
print(b)

## Length of the Set
print(len(b)) # Prints the length of this set

## Removal of an Item
b.remove(5) # Removes 5 fromt set b

How to Remove Items in a Set in Python Using the discard() Method

nameSet = {"John", "Jane", "Doe"}

nameSet.discard("John")

print(nameSet)
# {'Doe', 'Jane'}

How To Remove Elements From a Set using remove() function in python

mySet = {1, 2, 3}
mySet.remove(1)
print(mySet)


# Output:
# {2, 3}

How to Remove Items in a Set in Python Using the remove() Method

nameSet = {"John", "Jane", "Doe"}

nameSet.remove("Jane")

print(nameSet)
# {'John', 'Doe'}