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re.sub in python example

import re

result = re.sub(pattern, repl, string, count=0, flags=0);
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Python re.sub Examples

result = re.sub('abc',  '',    input)           # Delete pattern abc
result = re.sub('abc',  'def', input)           # Replace pattern abc -> def
result = re.sub(r's+', ' ',   input)           # Eliminate duplicate whitespaces using wildcards
result = re.sub('abc(def)ghi', r'1', input)    # Replace a string with a part of itself
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re sub python

# From Grepper Docs
>>> re.sub('-{1,2}', dashrepl, 'pro----gram-files')
'pro--gram files'
>>> re.sub(r'sANDs', ' & ', 'Baked Beans And Spam', flags=re.IGNORECASE)
'Baked Beans & Spam'
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Python RegEx SubString – re.sub()

import re

# Regular Expression pattern 'ub' matches the string at "Subject" and "Uber". As the CASE has been ignored, using Flag, 'ub' should match twice with the string Upon matching, 'ub' is replaced by '~*' in "Subject", and in "Uber", 'Ub' is replaced.
print(re.sub('ub', '~*', 'Subject has Uber booked already',
			flags=re.IGNORECASE))

# Consider the Case Sensitivity, 'Ub' in "Uber", will not be replaced.
print(re.sub('ub', '~*', 'Subject has Uber booked already'))

# As count has been given value 1, the maximum times replacement occurs is 1
print(re.sub('ub', '~*', 'Subject has Uber booked already',
			count=1, flags=re.IGNORECASE))

# 'r' before the pattern denotes RE, s is for start and end of a String.
print(re.sub(r'sANDs', ' & ', 'Baked Beans And Spam',
			flags=re.IGNORECASE))
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Python re.subn()

# Program to remove all whitespaces
import re

# multiline string
string = 'abc 12
de 23 
 f45 6'

# matches all whitespace characters
pattern = 's+'

# empty string
replace = ''

new_string = re.subn(pattern, replace, string) 
print(new_string)

# Output: ('abc12de23f456', 4)
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Python re.sub()

re.sub(pattern, replace, string)
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re.sub

re.sub(pattern,replacement,string)
re.sub finds all matches of pattern in string and replaces them
with replacement.
#Example
re.sub("[^0-9]","","abcd1234") #Returns 1234
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Python RegEx Subn – re.subn() Syntax

re.subn(pattern, repl, string, count=0, flags=0)
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Python RegEx Subn – re.subn()

import re

print(re.subn('ub', '~*', 'Subject has Uber booked already'))

t = re.subn('ub', '~*', 'Subject has Uber booked already',
			flags=re.IGNORECASE)
print(t)
print(len(t))

# This will give same output as sub() would have
print(t[0])
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Python re.sub Examples

result = re.sub("(d+) (w+)", r"2 1")
result = re.sub("(?<number>d+) (?<word>w+)", r"g<word> g<number>")
Comment

Python RegEx SubString – re.sub() Syntax

re.sub(pattern, repl, string, count=0, flags=0)
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