PYTHON

how to remove an element in a list by index python

list = [0, 1, 2, 3, 4, 5]

print(list)
# [0, 1, 2, 3, 4, 5]

del list[0]
print(list)
# [1, 2, 3, 4, 5]
      
del list[-2]
print(list)
# [1, 2, 3, 5]
      
del list[0:2]
print(list)
# [3, 5]

python list remove at index

>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> del a[-1]
>>> a
[0, 1, 2, 3, 4, 5, 6, 7, 8]

remove from list python by index

l = list(range(10))
print(l)
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

print(l.pop(0))
# 0

print(l)
# [1, 2, 3, 4, 5, 6, 7, 8, 9]

print(l.pop(3))
# 4

print(l)
# [1, 2, 3, 5, 6, 7, 8, 9]

remove element from list by index

letters = ["a", "b", "c", "d", "e"]
letters.pop(0)
letters.pop(1)
print(letters)
#pop will also return the value if you want to use it

how to remove element from specific index in list in python

list.pop(index)

how to remove element from list python by index

>>> l = [1, 2, 43, 3, 4]
>>> l.pop(2) #enter the index as argument
43
>>> l
[1, 2, 3, 4]

python remove by index

a = [0, 1, 2, 3, 4, 5]
el = a.pop(2)

python list remove at index

>>> del a[2:4]
>>> a
[0, 1, 4, 5, 6, 7, 8, 9]

python pop a element by index

a = ['a', 'b', 'c', 'd']
a.pop(1)

# now a is ['a', 'c', 'd']

how to remove an item from a certain index in python

arr = [0, 1, 2, 3, 4]
del arr[1]
# arr is now equal to [0, 2, 3, 4]

python list remove at index

a = ['a', 'b', 'c', 'd']
a.pop(1)

# now a is ['a', 'c', 'd']

remove from list python by index

print(l.pop())
# 9

print(l)
# [1, 2, 3, 5, 6, 7]

remove from list python by index

print(l.pop(-2))
# 8

print(l)
# [1, 2, 3, 5, 6, 7, 9]

remove from list python by index

l = list(range(10))
print(l)
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

l.clear()
print(l)
# []

remove from list python by index

# print(l.pop(100))
# IndexError: pop index out of range

List Remove At Index

var ls = new List<int>(){1,2,3,4,5};
ls.RemoveAt(2);
// ls elements 1,2,4,5
public void RemoveAt (int index);
Removes the element at the specified index of the List<T>.