Python

Search

Unique file name in django

from django.contrib.auth.models import User
def create_filepath(directory, instance, filename):
    new_filename = "%s.%s" % (User.objects.make_random_password(10),filename.split('.')[-1])
    return '/'.join([directory, new_filename])

Comment

PREVIOUS	NEXT

Code Example
Python :: access key through value python
::
Python :: python manually trigger exception
Python ::
Python :: Python Permutation without built-in function [itertools] for String
Python :: printing coloured and bold text in python
Python :: string replace in python
:: python logging change handler level
:: map in python
Python :: py environment variables register in flask
::
::
Python :: can i call a python script from a function
Python :: to_datetime with non zero padded values python
Python :: add a row at a specific index pandas
Python :: decision tree algorithm
Python :: tuple methods in python
Python :: python genap ganjil
Python :: pyplot aera
Python :: base64 python
Python :: tkinter window minsize
:: bar chart in python
Python ::
::
Python :: pure imagination
Python :: remove rows from a dataframe that are present in another dataframe?
Python :: any() and all()
Python :: threading in python
Python :: python download images from unsplash
Python :: np evenly spaced array

Search

PYTHON

Unique file name in django

ADD CONTENT