SQL

median mysql

SELECT x.val from data x, data y
GROUP BY x.val
HAVING SUM(SIGN(1-SIGN(y.val-x.val))) = (COUNT(*)+1)/2

median mysql

SET @rowindex := -1;
 
SELECT
   AVG(d.distance) as Median 
FROM
   (SELECT @rowindex:=@rowindex + 1 AS rowindex,
           demo.distance AS distance
    FROM demo
    ORDER BY demo.distance) AS d
WHERE
d.rowindex IN (FLOOR(@rowindex / 2), CEIL(@rowindex / 2));