SQL

select duplicates in sql

SELECT username, email, COUNT(*)
FROM users
GROUP BY username, email
HAVING COUNT(*) > 1

sql query to find duplicates in column

SELECT name, COUNT(email) 
FROM users
GROUP BY email
HAVING COUNT(email) > 1

sql how to duplicate a table

CREATE TABLE new_table LIKE original_table;
INSERT INTO new_table SELECT * FROM original_table;

get duplicate records in sql

Multiple field=
SELECT username, email, COUNT(*)
FROM users
GROUP BY username, email
HAVING COUNT(*) > 1

Single field=
SELECT _column, COUNT(*) 
FROM _table
GROUP BY _column
HAVING COUNT(*) > 1

how to get duplicate elements in sql

• SELECT first_name, COUNT (first_name) FROM employees
GROUP BY first_name
HAVING (COUNT(first_name) > 1);

SQL Duplicates by Composite

SELECT column1, column2, COUNT(*) as 'Count' 
FROM tablename 
GROUP BY column1, column2 
HAVING Count(*) > 1
ORDER BY [Count] DESC;

sql query duplicate rows

/* This SQL Query will show each of those duplicate
rows individually instead of just grouping it */
SELECT username,email 
FROM `users` 
WHERE `username` 
IN (SELECT username FROM `users` GROUP BY username HAVING COUNT(username) > 1)

how to deselct duplicates in sql

SELECT DISTINCT CITY FROM STATION WHERE ID%2=0;

sql duplicate rows

/*SELECT hotel_id, reservation_id, COUNT(hotel_id)FROM staywhere  reservation_id is not nullGROUP BY hotel_id, reservation_idHAVING COUNT(hotel_id) > 1*/select distinct s.hotel_id , t.* from stay sright join (    select hotel_id, reservation_id, count(*) as qty    from staywhere reservation_id !=1      group by hotel_id, reservation_id    having count(*) > 1) t on s.hotel_id = t.hotel_id and s.reservation_id = t.reservation_id