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python count number of digits in integer

import math
digits = int(math.log10(n))+1
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python count number of digits

num = 3452
count = 0

while num != 0:
    num //= 10
    count += 1

print("Number of digits: " + str(count))
Comment

how to count the number of the digits in an input in python

n=int(input("Enter number:"))
count=0
while(n>0):
    count=count+1
    n=n//10
print("The number of digits in the number are:",count)
Comment

count the total number of digits in a number pthon

number = str(input('enter number'))
i = 0
while i in range(len(number)):
    i +=1
print(f'Number of digits: {i}')
Comment

how to count digits in python

num = 123456
print(len(str(num)))
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