# You can use a lambda function, but you'll have to specify the index of the sorting key.
A = [[100, 'Yes'], [40, 'Maybe'], [60, 'No']]
print("Sorted List A based on index 0: % s" % (sorted(A, key=lambda x:x[0])))
B = [[2, 'Dog'], [0, 'Bird'], [7, 'Cat']]
print("Sorted List A based on index 1: % s" % (sorted(B, key=lambda x:x[1])))
# Also, you can use .sort() if you want to sort just by the first index
A = [[55, 90], [45, 89], [90, 70]]
A.sort()
print("New sorted list A is % s" % (A))
A.sort(reverse=True)
print("New reverse sorted list A is % s" % (A))
# You can even change the key sort, if you want to sort by length for example:
A = [[5, 90, 'Hi', 66], [80, 99], [56, 32, 80]]
A.sort(key=len) # <-
print("New sorted list A is % s" % (A))
from operator import itemgetter
A = [[10, 8], [90, 2], [45, 6]]
print("Sorted List A based on index 0: % s" % (sorted(A, key=itemgetter(0))))
B = [[50, 'Yes'], [20, 'No'], [100, 'Maybe']]
print("Sorted List B based on index 1: % s" % (sorted(B, key=itemgetter(1))))
"""Sort in ascending and descending order"""
list_test = [2, 1, 5, 3, 4]
#ascending is by default for sort
#Time Complexity: O(nlogn)
list_test.sort()
#For descending order
#Time Complexity: O(nlogn)
list_test.sort(reverse=True)
#For user-define order
list_test.sort(key=..., reverse=...)