SQL

sql count duplicate rows

SELECT _column, COUNT(*) 
FROM _table
GROUP BY _column
HAVING COUNT(*) > 1

t-sql get duplicate rows

SELECT [CaseNumber], COUNT(*) AS Occurrences
FROM [CaseCountry]
GROUP BY [CaseNumber]
HAVING (COUNT(*) > 1)

duplicate records in sql

Multiple field=
SELECT username, email, COUNT(*)
FROM users
GROUP BY username, email
HAVING COUNT(*) > 1

Single field=
SELECT _column, COUNT(*) 
FROM _table
GROUP BY _column
HAVING COUNT(*) > 1

how to get duplicate values in sql

• SELECT first_name, COUNT (first_name) FROM employees
GROUP BY first_name
HAVING (COUNT(first_name) > 1);

sql find duplicate records in two tables

SELECT  *   
FROM TableA A  
WHERE NOT EXISTS (SELECT *      
                  FROM TableB B
                  WHERE A.NUM = B.NUM);

sql query duplicate rows

/* This SQL Query will show each of those duplicate
rows individually instead of just grouping it */
SELECT username,email 
FROM `users` 
WHERE `username` 
IN (SELECT username FROM `users` GROUP BY username HAVING COUNT(username) > 1)

sql - Count all duplicates of each value

SELECT   col,
         COUNT(dupe_col) AS dupe_cnt
FROM     TABLE
GROUP BY col
HAVING   COUNT(dupe_col) > 1
ORDER BY COUNT(dupe_col) DESC

sql duplicate rows

/*SELECT hotel_id, reservation_id, COUNT(hotel_id)FROM staywhere  reservation_id is not nullGROUP BY hotel_id, reservation_idHAVING COUNT(hotel_id) > 1*/select distinct s.hotel_id , t.* from stay sright join (    select hotel_id, reservation_id, count(*) as qty    from staywhere reservation_id !=1      group by hotel_id, reservation_id    having count(*) > 1) t on s.hotel_id = t.hotel_id and s.reservation_id = t.reservation_id