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Recipe 16.8 Switching Unknown Pointer TypesProblemYou need a generic method that accepts two pointers and switches the addresses that each pointer points to. In other words, if X points to an integer variable Foo and Y points to an integer variable Bar, you want to switch X so that it points to Bar and switch Y so that it points to Foo. SolutionCreate a method that accepts two void pointers. The following method accepts two pointers to void by reference. The by reference is required since we are actually switching the values contained in the pointer variables, not the value that the pointer is pointing to: public unsafe void Switch(ref void* x, ref void* y) { void* temp = x; x = y; y = temp; } The following test code calls the Switch method with two integer variables that point to different memory locations: public unsafe void TestSwitch( ) { int x = 100; int y = 20; int* ptrx = &x; int* ptry = &y; Console.WriteLine(*ptrx + "\t" + (int)ptrx); Console.WriteLine(*ptry + "\t" + (int)ptry); // Convert int* to void* void* voidx = (void*)ptrx; void* voidy = (void*)ptry; // Switch pointer values Switch(ref voidx, ref voidy); // Convert returned void* to a usable int* ptrx = (int*)voidx; ptry = (int*)voidy; Console.WriteLine(*ptrx + "\t" + (int)ptrx); Console.WriteLine(*ptry + "\t" + (int)ptry); } The following is displayed: 100 1243108 20 1243104 20 1243104 100 1243108 The TestSwitch method could just have easily been written with another data type, such as a byte, shown here: public unsafe void TestSwitch( ) { byte x = 100; byte y = 20; byte* ptrx = &x; byte* ptry = &y; Console.WriteLine(*ptrx + "\t" + (int)ptrx); Console.WriteLine(*ptry + "\t" + (int)ptry); // Convert byte* to void* void* voidx = (void*)ptrx; void* voidy = (void*)ptry; // Switch pointer values Switch(ref voidx, ref voidy); // Convert returned void* to a usable byte* ptrx = (byte*)voidx; ptry = (byte*)voidy; Console.WriteLine(*ptrx + "\t" + (int)ptrx); Console.WriteLine(*ptry + "\t" + (int)ptry); } All that had to be done is to change the int* types to byte* types. DiscussionA void pointer has no type and therefore cannot be dereferenced, nor can pointer arithmetic be applied to this type of pointer. A void pointer does have one very useful function, though; it can be cast to a pointer of any other type. A void pointer is also able to be cast to the following other value types as well:
In the Switch method, used in the Solution for this recipe, we notice that it takes two parameters by reference of type void*. We are declaring that any pointer type may be passed to these two parameters on this method. Once inside the Switch method, we can manipulate the value contained in the void pointers. However, since we do not know the original type that the void* was cast from, we cannot dereference the void*. The one drawback to this technique is that before the Switch method is called in the TestSwitch method, the int* or byte* pointers must be cast to a void*. When the Switch method returns, the void* pointers must be cast back to their original types before they may be used. The reason for this casting is that we are passing the void* pointers by reference instead of by value. We could pass the void* pointers by value instead, and simply switch the values pointed to, rather than the memory locations pointed to, in the Switch method. This new SwitchValues method would look something like this: public unsafe void SwitchValues(void* x, void* y) { void* temp = x; *x = *y; *y = *temp; } Unfortunately, this code will not compile, since you cannot dereference a void*. The void* must be cast to its original type before it can be dereferenced. To do this, we must also pass along the type information to the SwitchValues method. This can become very cumbersome, and it will reduce the genericity of this method as well. See AlsoSee section A.4 Pointer conversions in the C# specification. |
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