# This is a binary XOR
True ^ True # = False, as expected for xor
# For integers it's more complicated. First we change the integers to
# binary. Then we take each column one at a time and do xor on them.
8 ^ 3 # = 11.
"""
1000 # 8 (binary)
0011 # 3 (binary)
---- # APPLY XOR to each column
1011 # result = 11 (binary)
"""