CODE EXAMPLE FOR PHP

update image in database using php

<?php
    	require_once 'conn.php';
    	if(ISSET($_POST['save'])){
    		$image_name = $_FILES['photo']['name'];
    		$image_temp = $_FILES['photo']['tmp_name'];
    		$firstname = $_POST['firstname'];
    		$lastname = $_POST['lastname'];
    		$exp = explode(".", $image_name);
    		$end = end($exp);
    		$name = time().".".$end;
    		if(!is_dir("./upload"))
    			mkdir("upload");
    		$path = "upload/".$name;
    		$allowed_ext = array("gif", "jpg", "jpeg", "png");
    		if(in_array($end, $allowed_ext)){
    			if(move_uploaded_file($image_temp, $path)){
    				mysqli_query($conn, "INSERT INTO `user` VALUES('', '$firstname', '$lastname', '$path')") or die(mysqli_error());
    				echo "<script>alert('User account saved!')</script>";
    				header("location: index.php");
    			}	
    		}else{
    			echo "<script>alert('Image only')</script>";
    		}
    	}
    ?>